Question

The equation of the tangent to the curve Y =secx at the point ( 0,1 ) is​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer :

y = 1 is the equation of the tangent to the given function y = sec x

Given an equation y = sec x and the equation of the tangent to the given equation y = sec x is to be found.

Now, differentiating the given function y = sec x

dy/dx = sec x . tan x

now the slope of the function at the given point (0,1) is

sec(0).tan(0) = 1.0 = 0

So, the equation of the tangent to the curve y = sec x is

(y - 1)/(x - 0) = 0

(y - 1)/x = 0

y - 1 = 0

y = 1

y = 1 is the equation of the tangent to the given function y = sec x

So, to conclude in a sentence, the equation of the tangent to the given function y = sec x is y = 1.

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