Complex numbers are often used when dealing with alternating current (AC) circuits. In the equation V = IZ, V is voltage, I is current, and Z is a value known as impedance. If V = 1-i and Z=1+3i, find I. Express your answer as a complex number in the form a+bi, where a and b are real numbers.
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Answer:
-1/13-5i/13
Step-by-step explanation:
Multiplying the numerator and denominator by the conjugate of the denominator, we have:
(1-i)/(2+3i)*(2-3i)/(2-3i)= [1(2) + 1(-3i) - i(2) - i(-3i)]/[2(2) + 2(-3i) + 3i(2) -3i(3i)]
= (-1-5i)/13
= -1/13-5i/13
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