component of velocity of a particle as follows vx =5t m/s, vy =7t m/s. what will be acceleration of a particle :-(in m/s²)
Answers
Answered by
0
Acceleration along x-axis
ax = d(vx)/dt = 5 m/s²
Acceleration along y-axis
ay = d(vy)/dt = 7 m/s²
Acceleration = √(5² + 7²) m/s²
= 8.6 m/s²
Acceleration of particle is 8.6 m/s²
ax = d(vx)/dt = 5 m/s²
Acceleration along y-axis
ay = d(vy)/dt = 7 m/s²
Acceleration = √(5² + 7²) m/s²
= 8.6 m/s²
Acceleration of particle is 8.6 m/s²
Answered by
0
dv/dtin X direction equal to 5 acceleration in y direction is 7 acceleration is 74
JunaidMirza:
Acceleration is √74 m/s²
Similar questions