Question

compound has the following composition- N- 35%.H- 5%,0 - 60% IN 14 H-1. o- 16] 11 Determine the empirical formula. 2) If the relative molecular mass is 80 find the molecular formula 3jif the above compound is a nitrate, write the name of the compound please answer
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Answer 1

Answer:

1. N2H4O3

2.N2H4O3

3.NH4NO3

Explanation:

i)

element   %comp    at wt.   relative no. of atoms       simplest ratio

  N                35         14            35/14=  2.5                      2.5/2.5= 1x2 = 2

  H                  5           1               5/1=     5                         5/2.5=  2x2  = 4        

  O                60         16             60/16= 3.75                  3.75/2.5= 1.5x2 = 3

Emperical formula= N2H4O3

ii)

Emperical formula wt. = 14x2 +2x5 +16x3 = 80

n = Emperical formula wt.   = 80/80 = 1

    relative molecular mass

molecular formula= n[Emperical formula]

                                = 1xN2H4O3

                                = N2H4O3

iii) we know that the compund  is a nitrate,

    if u take no3 out, ur left with 1 N and 4H,

    so the compund is NH4NO3