Math, asked by abhishek012, 1 year ago

compound interest questions plz solve it

Attachments:

Answers

Answered by Atreyee26
2
I think the answer is 2777.77(approximately)

abhishek012: how yu have done
Atreyee26: with the help of the formula of "Uniform Rate of Decrease"
abhishek012: wt is the formula
Atreyee26: p(1-r/100)^n
Atreyee26: p=original ,n=year
abhishek012: but answer is wrong
abhishek012: the answer is 25000
abhishek012: plz tell
Atreyee26: maine jo socha wahi kiya..ab mujhe nahi pata
abhishek012: okh
Answered by wifilethbridge
1

Answer:

Rs.25000

Step-by-step explanation:

Let the original cost be x

We are given that the value of machine depreciates every year by 10 %

So, Cost after 1 year = x-\frac{10}{100}x

Again the value of machine depreciates  by 10 %

Now amount of depreciation in second year =  10\%(x-\frac{10}{100}x)

We are given that the cost depreciates by Rs.2250 during second year

So,  10\%(x-\frac{10}{100}x) = 2250

\frac{10}{100}(x-\frac{10}{100}x) = 2250

x=25000

Hence The original value of machine is Rs.25000

Similar questions