Compounds which show chemical properties like their elements
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To know the amount or volume of NaOH to prepare 400 mL of 1.5 M NaOH, we use formula
M1 X V1 = M2 X V2
V1 = M2 X V2/ M1
But before that we will convert 400 mL into litre = 0.4 L
5.5 X V1 = 1.5 M x 0.4 L
V1 = 1.5 M X 0.4L/ 5.5
V1= 0.10 L
V1 = 100mL
So, you need 100mL of 5.5 NaOH
M1 X V1 = M2 X V2
V1 = M2 X V2/ M1
But before that we will convert 400 mL into litre = 0.4 L
5.5 X V1 = 1.5 M x 0.4 L
V1 = 1.5 M X 0.4L/ 5.5
V1= 0.10 L
V1 = 100mL
So, you need 100mL of 5.5 NaOH
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