Question

Comprehension-IV
On being heated in oxygen 5.72 g of red metallic oxide
A was converted to 6.36 gram black metallic oxide B.
When 4.77 g of B was heated in a stream of H2 gas,
3.81 g of metal M was formed. (Given, atomic weight of
metal is 63.50)
Choose the correct answer :
1. The formula of red metallic oxide A is
(1) MO
(2) MOZ
(3) M.O
(4) M2O3
2. The formula of black metallic oxide is
(1) MO
(2) M205
(3) M2O3
(4) MO
3. The equivalent weight of metal M in B is
(1) 118.9
(2) 65.4
(3) 63.5
(4) 31.8​

Answer 1

Answer:

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Explanation:

Answer 2

choose the correct answer 1)=m.o

2)=Since metallic oxide is MO hence metal must be in M2+ form therefore its nitrate will be M(NO3)

3=118.9

expaination:hope its helps