Math, asked by xyz8985, 1 year ago

compute (2^-9÷2^-11)^3

Answers

Answered by DeeptiMohanty
17
Here is your answer....

 =     ({\frac{ {2}^{ - 9} }{ {2}^{ - 11} }})^{3}  \\  \\  =  \frac{ {2}^{ - 27} }{ {2}^{ - 33} }  \\  \\  as \: we \: know \\  \\  \frac{ {a}^{m} }{ {a}^{n} }  =  {a}^{m - n}  \\  \\  =  ({2})^{( - 27 - ( - 33))}  \\  \\ =  {2}^{ ( - 27 + 33)}  \\  \\  =   {2}^{6}  \\  \\  = 64

Hope this helps you....✌✌
Answered by occasionzevents5
0

Answer:

64 is the answer hope its helpful

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