Compute: limx→0x2ex-1
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Note 1 If limx→a g(x) = 0 and limx→a f(x) = b, where b is a finite number with b 6= 0, Then:
the values of the quotient f(x)
g(x)
can be made arbitrarily large in absolute value as x → a and thus
1
the limit does not exist.
If the values of f(x)
g(x)
are positive as x → a in the above situation, then limx→a
f(x)
g(x) = ∞,
If the values of f(x)
g(x)
are negative as x → a in the above situation, then limx→a
f(x)
g(x) = −∞,
If on the other hand, if limx→a g(x) = 0 = limx→a f(x), we cannot make any conclusions about
the limit.
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