Question

compute the heat generated while transferring 96000 C of charge in one hour through a potential difference of 50V​

Answer 1

Answer:

4800 kilojoules

Explanation:

Given:

Charge = q = 96,000 C

Potential difference = v = 50 V

Time = 1 hour

1 hour = 60 minutes; 1 minute = 60 seconds

1 hour = 60×60 seconds = 3600 seconds

To find:

Heat generated

Current = $\frac{q}{t} ; where\ q \ is \ charge \ and \ t \ is\ time$

Current= $\frac{96000}{3600}$

Current = $\frac{80}{3} amperes$

Heat generated = v×i×t

Heat generated = 50×$\frac{80}{3}$×3600

Heat generated = 4800 kilojoules

The heat produced is 4800 kilojoules

Answer 2

Given

● Charge given = 96000 C

● Potential difference = 50 V

● Time = 1 hour.

To find

● Heat generated

Solution

Here v = 50V

Charge (q) = 96000 C

Time = 1 hour

⇒ Time = (1 × 3600) s

⇒ Time = 36000 s

Using formula :

⋆ Current (I) = Charge(q)/Time(t)

⇒ I = 96000/3600

⇒ I = 960/36

⇒ I = 26.67 A

∴ Current flowing = 26.67 A

Again using formula :

⋆ Current = Voltage/Resistance

⇒ 26.67 = 50/Resistance

⇒ Resistance = 50/26.67

⇒ Resistance = 1.87 ohm.

Now we know that,

⋆ Heat produced (H) = I²Rt

⇒ H = (26.67)² × 1.87 × 3600

⇒ H = 711.2889 × 1.87 × 3600

⇒ H = 4788396 J

⇒ H = 4788.396 kJ

∴ Heat produced = 4788396 J or 4788.396 kJ