Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V. *
(a) 48000 joule
(b) 480000 joule
(c) 4800000 joule
(d) 48000000 joule
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H=VIt
V=50 v
t=1×60×60
=3600
I=Q/t
=96000/(1×60×60)
=96000/3600
=960/36
I=960/36
H= VIt
=50×(960/36)×3600
=4800000
H=4800000
therefore c is the ans
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