Compute the (i) distance travelled and (ii) displacement made by
the student when he travels a distance of 4km eastwards and
then a further distance of 3 km northwards.
vatsal:
he would travel a DISTANCE of 7 km(4 km + 3 km)
and he has been displaced by or makes a displacement of 5 km
plz tell ur class and board .........and i would explain accordingly.........:)
Answers
Answered by
7
distance travelled = 4+3 = 7Km.
displacement = shortest distance between two points
= √(4²+3²)
= √25
= 5Km.
displacement = shortest distance between two points
= √(4²+3²)
= √25
= 5Km.
Answered by
2
(i)distance=4+3=7 km
(ii)displacement=(4^2+3^2)^1/2
=(5^2)^1/2=5 km
(ii)displacement=(4^2+3^2)^1/2
=(5^2)^1/2=5 km
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