Question

compute the
number of
ions present
in
11.7g of
sodium
chloride.​

Answer 1

Answer:

NacL -23+58.5=58.5g (Molarmass-sum of atomic masses)  

Nacl-23  

cl-35.5  

a 58.5g nacl contains 23 grams of na  

23 in 58.5g  

there fore xgrams of na is present in 11.7g  

x in 11.7g  

x/23 =11.7/58.5  

x= 23* (11.7/58.5)=4.60g =~0.2mole

Answer 2

Answer:

muje delete krna Ni Aata isiliye bta Ra hun glt Hai

23 Ki jgh 58.5 aana Hai toh 23.4/58.4= nearly O.28