compute the number of Ions present in 5.8 gram of sodium chloride
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Answered by
1
Answer:
Explanation:
According to given data,
5.85 g of NaCl= 58.5/5.85
=0.1 moles of NaCl particle
Each NaCl particle contains 2 ions Na+ and Cl−
⇒ Total moles of ions =0.1×2 =0.2 moles
No. of ions =0.2×6.022×10^23
=1.2042×10^23 ions
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Answer:
5.0
Explanation:
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