Question

Compute the speed of 2kg ball having kinetic energy of 4J.​

Answer 1

Answer:v=2m/s

Explanation: 4=1/2*2*v^2

V^2=4 V=2

Answer 2

ANSWER

Given,

mass of ball,m = 2 kg

K.E of ball= 4J

As,

K.E =

$\frac{1}{2} m {v}^{2}$

therefore,

${v}^{2} = \frac{2k.e}{m}$

$= \frac{2 \times 4}{2}$

= 4

$= > v = 2m \: per \: second$

THANKS