Math, asked by mysticd, 1 year ago

Compute the sum of all roots of
(2x+3)(x-4)+(2x+3)(x-6)=0

Answers

Answered by john44
4
2x^2 -5x -12 + 2x^2 -9x -18 = 0
4x^2-14x-30= 0....(2)
2x^2-7x- 15= 0
2x^2 - 10x +3x -15 = 0
x= -3/2or x = 5
therefore sum = 7/2
or
from 2,
alpha + beta = -b/a
= -(-14)/4
= 7/2
Answered by EruptingLava
2

Answer:

2x^2 -5x -12 + 2x^2 -9x -18 = 0 4x^2-14x-30= 0...(2)

2x^2-7x- 15= O 2x^2 - 10x +3x -15 = 0

x= -3/2 or x = 5

therefore sum = 7/2

or

from 2,

alpha + beta = -b/a

= -(-14)/4 = 7/2

Step-by-step explanation:

Hope it will help

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