Compute the value of x
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Solñ: Let, angle B=x
∆EAC=180°
»angle EAB+angle BAC=180°
»120°+angle BAC=180°
»angleBAC=180°-120°=60°
Again,
∆BCD=180°
»angle ECD+angle BCA=180°
»112°+angle BCA =180°
»angleBCA=180°-112°
»angleBCA=68°
Therefore,
∆ABC=180°
»angleBAC+ angle ABC + angle BCA=180°
»60°+68°+ angle ABC=180°
»angleABC=180°-128°
angle ABC=52°
:. angle ABC=x=52°
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