Question

Find three consecutive numbers in AP such that their sum is 27 and the third number is double the first number.

Answer 1

This is the way a.a plus d.a minus d

Answer 2

Hey mate,

The sum of first three consecutive number in AP is 27and there product is 504, find them?

The three consecutive numbers would be

( a -d ),a , ( a + d )

So their sum will be

a-d + a + a+d = 27

a = 9

Now the product would be

(a-d)(a)(a+d)=504

(9-d)9(9+d) = 504

( 9^2 - d^2 ) = 504 / 9

81-d^2 = 56

d^2 = 25

d=5

So the terms are

(9–5) , 9 , ( 9+5 )

4 , 9 , 14

Hope it will help you.