concentrated aqueous sulphuric acid is98% h2so4 by mass and a density of1.80g/ml . volume of acid required to make one litre of 0.1M h2so4
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Answer: Volume=0.0055L
Explanation:
Let us assume that 100g solution contains 98g of H2SO4 by mass.
Since the solution is aqueous so mass of water is 2g.(100-98=2g H2O by mass)
Molar mass of H2SO4= 98g (2×1+32×1+16×4=98g)
Therefore moles of H2SO4=1 moles
Density=mass solution/volume solution
1.8g/ml = 100g/volume of solution
Volume of solution = 1000/18 ml
Now
Molarity(M1) = moles of H2SO4/Volume of solution
M1 = 1/55.55×10^-3L (1000/18=55.55 ml)
M1 = 18M
And assume required volume be V1
Also Volume V2= 1L (given)
And Molarity M2= 0.1M(given)
From definition of dilution we know,
Moles of solute are same in both the solution before and after dilution,
Therefore, M1V1 = M2V2
18×V1 = 0.1×1
V1 = 0.0055L
Hope it helps...
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rtrrahul:
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