concentrated sulphuric acid is 49% by mass and has a density of 1.5 g per cm3. Calculate molarity and molality of concentrated sulphuric acid
Answers
33.4 mL volume of the stock solution for it's 49% (w)w solution as: Solution:- Stock solution is 49%(w/w). It means 49 grams of sulfuric acid 100g (1959) present in 100 grams of the solution. = 66.7 mL We want to make 2.5 L of 0.1 M It means 49 grams of sulfuric acid sulfuric acid solution from the stock are present in 66.7 ml solution. We solution. let's calculate the moles need to calculate the volume of this and then grams of this diluted stock solution that would contains solution from it's given volume and 24.5 grams of sulfuric acid. molarity as: 2.5L(-Imolot 24.59H2SO4(661092) = 24.5 g = 33.4mL H2SO4 Density of the stock solution is 1.5 So, 33.4 mL of stock solution are gram per mL. Let's calculate the required to make 2.5 L of 0.1 M volume of the stock solution for it's it's sum sulfuric acid solution.