Question

Conductivity of 2.5 into 10 to the power minus 4 molar methanoic acid is 5.25 into 10 to the power minus 5

Answer 1

^=k/c 5.25×10^-5/2.5×10^-4=2.1×10^-2

Alpha=^/^°=2.11×10^-2/4.04×102 =0.519

Answer 2

k/c 5.25×10^-5/2.5×10^-4

=2.1×10^-2

Alpha=^/^°

=2.11×10^-2/4.04×102

=0.519