Question

Conductivity of 2 x 10-M methanoic acid is 8 x 10-5 S cm-1 Calculate
its molar conductivity and degree of dissociation if i'm for methanoic
acid is 404 S cm mol-1.

Answer 1

Answer:

The molar conductivity of OH- is 3-5 times the conductivity of other small anions. To calculate the conductivity of a solution you simply multiply the concentration of each ion in solution by its molar conductivity and charge then add these values for all ions in solution.

Explanation:

Answer 2

Molar Conductivity is $400\ S\ cm^2 mol^{-1}$

Explanation:

We know that,

• Molar Conductivity is what a mole of electrolyte ions gives as conductance which further gives increment to degree of dissociation and finally molar conductivity.  

• Molar Conductivity,$(\lambda_m) = \frac {1000 \times Conductivity(k)}{Concentration(c)}$

So,  

$(\lambda_m) = \frac {1000 \times 8 \times 10^{-5}}{2\times 10^{-4}}= 400\ S\ cm^2 mol^{-1}$

Hence,  

$\lambda^0_{CH_3COOH} = \lambda^0_{H^+} + \lambda^0_{HCOO^-}$

= $(349.5+50.5) = 400\ S\ cm^2mol^{-1}$

• Degree of Dissociation, $\alpha = \frac {\lambda_m}{\lambda_0}$

= $\frac {400}{404}$

= 0.99

or $\alpha = 99.99$%