Question

Congruence of Triangles and Inequalities in a Triangle
In the given figure, ACDE is an equilateral A
triangle on a side CD of a square ABCD. Show that
AADE = ABCE.
jare ABCD and an equilat​

Answer 1

Answer:

∠ADC=∠BCD=90

∘

→square

∠CDE=∠DCE=60

∘

→equilateral_triangle

∴∠ADE=∠BCE=150

∘

InΔADEandΔBCE

AD=BC

DE=CE

∠ADE=∠BCE

ΔADE≅ΔBCE