Question

Connect three resistors R1, R2and R3 of 4 Ohm each in parallel across the battery of 16V. Also connect ammeter and voltmeter in the circuit. Find :-
a)Total resistance of the circuit.
b)Total current flowing through the circuit.
c)Current flowing through resistor R1.
d)Energy and power used by R2 resistor in 10 seconds.

Answer 1

a) 1/r1+1/r2+1/r3=1/4+1/4+1/4=3/4
b)V=IR so
16=(i)3/4
16
-------=(i)
3/4
16×4/3
21.3..
c)16/4 :V/R
=4
d)sorry I don't know how to calculate.......

But mark me as brillianist

Answer 2

a) total resistance of circuit:

since all resistance having magnitudes each 4 ohm and connected in parallel.
1/R=1/4+1/4+1/4
R= 4/3 ohm
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b)Total current flowing in the circuit:

we know what:
v=IR
given ,v=16volt and R=4/3 ohm
I=V/R=16×3/4=12 Ampere
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c)current through R1:

I(1)=4×12/12=4A
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please mark me brainliest
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d)work or energy and power:
energy= VIt
=16×12×10
=1920 joule
power=energy/time
=16× 12=192 watt