Consecutive odd no the sum of squares is/394
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± 13 & ± 15
Step-by-step explanation:
Let say consecutive odd numbers are
2n-1 & 2n+1
Sum of their squares = 394
(2n-1)² + (2n+1)² = 394
=> 4n² + 1 - 4n + 4n² + 1 + 4n = 394
cancelling 4n
=> 8n² + 2 = 394
=> 8n² = 394 -2
=> 8n² = 392
=> n² = 49
=> n² = (± 7)²
=> n = ± 7
Case 1 - When n =7
2n-1 = 2 * 7 - 1 = 13
2n + 1 = 2*7 + 1 = 15
So consecutive odd numbers are 13 & 15
case 2 when n = -7
2n - 1 = 2 * (-7) - 1 = -15
2n + 1 = 2 * (-7) + 1 = -13
Consecutive odd numbers are -13 & -15
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