consider 2 equal vectors at an angle theta. show that their resultant divides angle theta. also find their resultant
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If the magnitude of the resultant of two equal vectors is equal to that of either vector, find the angle between them.
My Attempt: Let a⃗ a→ and b⃗ b→ be two vectors such that ∥a⃗ ∥=∥b⃗ ∥‖a→‖=‖b→‖
Magnitude of Resultant:
=a2+b2+2abcosθ−−−−−−−−−−−−−−√=a2+b2+2abcosθ
=2a2+2abcosθ−−−−−−−−−−−−√=2a2+2abcosθ
How do I proceed further?
My Attempt: Let a⃗ a→ and b⃗ b→ be two vectors such that ∥a⃗ ∥=∥b⃗ ∥‖a→‖=‖b→‖
Magnitude of Resultant:
=a2+b2+2abcosθ−−−−−−−−−−−−−−√=a2+b2+2abcosθ
=2a2+2abcosθ−−−−−−−−−−−−√=2a2+2abcosθ
How do I proceed further?
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