Question

Consider 3 non-collinear points
A(9,3), B(7,-1), and C(1,-1). Let P(a, b)
be the centre and R is the radius of circle ‘S'
passing through points A,B,C. Also
Hã, j) are the coordinates of the orthocentre
of triangle ABC whose area be denoted by A.
62. IfD,E and F are the middle points BC, CA and
AB respectively then the area of the triangle
DEF is :
A) 12 B)6 C) 4 D) 3​

Answer 1

Answer:

ans = 3

so area of the traingle DEF is 3 unit square.

Answer 2

Answer:

D) 3

Step-by-step explanation:

Given:

A(9,3)

B(7,-1)

C(1,-1)

mid points of

• BC is D

= (7+1,-1+(-1))/2

=(8,-2)/2

=( 4,-1)

• CA is E

=(1+9,(-1+3)/2

=(5,1)

• AB is F

=(9+7,(-1+3))/2

= (8,1)

for area of a triangle DEF

= ½ (4(1-1)+5(1+1)+8(-1-1))

=½× 6

=3 units.

hence ,

area of triangle DEF is 3.

(#SPJ3)