Question

Consider 3ʳᵈ orbit of He⁺ (Helium), using non-relativistic
approach, the speed of electron in this orbit will be [given
K = 9 × 10⁹ constant, Z = 2 and h (Plank's Constant)
= 6.6 × 10⁻³⁴ J s] [2015]
(a) 1.46 × 10⁶ m/s (b) 0.73 × 10⁶ m/s
(c) 3.0 × 10⁸ m/s (d) 2.92 × 10⁶ m/s

Answer 1

Answer:

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Explanation:

v=(2.19×10

6

)

n

Z

v=(2.19×10

6

)

3

2

v=1.46×10

6

m/s