Question

Consider 3rd orbit of He⁺ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [givenK = 9 × 10⁹ constant, Z = 2 and h (Plank's Constant) = 6.6 × 10⁻³⁴ J s](a) 1.46 × 10⁶ m/s(b) 0.73 × 10⁶ m/s(c) 3.0 × 10⁸ m/s(d) 2.92 × 10⁶ m/s

Answer 1

$\huge\bf\orange{QUESTION:-}$

Consider 3rd orbit of He⁺ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [givenK = 9 × 10⁹ constant, Z = 2 and h (Plank's Constant) = 6.6 × 10⁻³⁴ J s]

(a) 1.46 × 10⁶ m/s

(b) 0.73 × 10⁶ m/s

(c) 3.0 × 10⁸ m/s

(d) 2.92 × 10⁶ m/s

$\huge\bf\red{ANSWER:-}$

option B is the correct answer

Answer 2

Answer:yeah dudes... Its given in this attachment

Explanation: