Question

Consider 615 ml of a 0.152 m hclo solution (ka = 3.510-8). What mass (in g) of naoh do you need to add to make a solution with ph = pka? (assume no volume change) ______ g naoh what mass (in g) of naoh do you need to add to make a solution with ph = 7.97? (assume no volume change) _______g naoh what mass (in g) of naoh do you need to add to make a solution with ph = 6.57? (assume no volume change) ______g naoh

Answer 1

I have not understood your question

Answer 2

Answer:

Quite simply, you multiply 2,500 by 4% (= 0.04) and then by 3, which gives you Rs 300. You are able to do this because you have specified simple interest. If interest were compounding, the math would get a little harder.