the difference of two no is 14 and difference in their squares is 448. find numbers
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Let the two numbers be x y
x-y=14
x^2-y^2=448
(x-y)(x+y)=448
14(x+y)=448
x+y=448/14
x+y=32
solve x+y and x-y
2x=14+32
2x=46
x=23
y=x-14
y=23-14
y=9
Therefore the numbers are 23,9
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x-y=14
x^2-y^2=448
(x-y)(x+y)=448
14(x+y)=448
x+y=448/14
x+y=32
solve x+y and x-y
2x=14+32
2x=46
x=23
y=x-14
y=23-14
y=9
Therefore the numbers are 23,9
HOPE THIS HELPS YOU BUDDY ✌️
IF YOU LIKE IT PLEASE MARK IT AS BRAINLIEST!!!
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Here is your answer.
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Hope it helps you.
Plzzz mark me as brainliest.
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