Question

Consider a bar magnet having length 5 cm and pole strength 8Am. What will be the magnitude of magnet on the line, which is along the axis of magnet?​

Answer 1

Answer:

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Answer 2

Given:

Consider a bar magnet having length 5 cm of pole strength 8Am.

To Find:

What will be the magnitude of magnet on the line, which is along the axis of magnet?​

Solution:

Here, it is given that -

Length of the magnet = $\[2l = 5cm = 5 \times {10^{ - 2}}m\]$,

pole strength = m= 8 A-m.

Since, magnetic field intensity of north pole is-

$\[\begin{gathered} {H_N} = \left( {\dfrac{{{\mu _0}}}{{4\pi }}\dfrac{m}{{{l^2}}}} \right)/{\mu _0} \hfill \\ = \dfrac{m}{{4\pi {l^2}}} \hfill \\ \end{gathered} \]$

and magnetic field intensity of south pole is-

$\[{H_S} = \dfrac{m}{{4\pi {l^2}}}\]$

therefore, magnetic field intensity along the axis of magnet is -

$H=H_{N}+H_{S} \\\\=\dfrac{2m}{4\pi(l^{2}) }\\\\=\dfrac{m}{2\pi(l^{2} )}$

on substituting the value of 'm' and 'l' , we have

$\[\begin{gathered} H = \dfrac{8}{{2 \times 3.14 \times 25 \times {{10}^{ - 4}}}} \hfill \\ = 0.050955 \times {10^4} \hfill \\ = 509.55 \hfill \\ \end{gathered} \]$

Thus, the magnitude of magnet on the line, which is along the axis of magnet is $509.55 A/m^{2}$.