Question

Consider a car moving on a straight road with a speed of 100 m/s. the distance at which car can be stopped is [μk = 0.5] 100 m/s

Answer 1

HELLO FRIEND HERE IS YOUR ANSWER,,,,

Given,,,,

$u \: \: = \: \: 100 m/s$

$\mu_s = 0.5$

$\therefore$ The equation for a straight line of motion us calculated by the 3rd Kinematical Equation,, which is ,

$v^2 = u^2 + 2as$

And , we know that ,,,

$a = \mu g$

$\therefore$ By substituting the given values from the question into this newly formed Equation including Equation of acceleration,,, we get,

$v^2 = u^2 + 2 (\mu \times g) \times s$

Substitute the values for $\mu = 0.5$, $u = 100 m/s$ and gravitational constant , that is , "g" = 10.

$\therefore (0)^2 = (100)^2 - 2 \times (\mu \times g) \times s$

$\implies$

$s = \frac{(100)^2}{2 \times 0.5 \times 10}$

$\therefore \: \: s = \frac{10000}{10}$

$\therefore \: \: s = 1000 \; m$

Which is the required solution for this type of query presented...

HOPE IT HELPS YOU AND SOLVES ALL YOUR DOUBTS RELATING TO FRICTIONAL BODIES AND / OR TO FIND THE STOPPING DISTANCE!!!!!!

Answer 2

Answer:

1000m

Explanation:

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