Question

consider a duct of square cross section of side 'b' the hydraulics radius is given by​

Answer 1

Answer:

we can equate the area in this case

so pi×r^2=b^2

so r=b/(pi)^1/2

hope it helps

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Answer 2

Answer:

radius = area/2(wetted perimeter)

Explanation:

R = b²/2(2b +b)

R =b/6