Question

CONSIDER A LARGE FISH THAT SWIMS TOWARDS AND SWALLOW A SMALL FISH AT REST.IF THE LARGE FISH HAS A MASS OF 5 KG AND SWIMS AT 1 M/S TOWARDS THE SMALL FISH HAVING MASS OF 1 KG WHAT IS VELOCITY OF FISH IMMIDIATELY AFTER THE LUNCH

Answer 1

Answer:

5.02

Explanation:

take the mass ÷ by velocity add one fraction of the mass it just gained

Answer 2

Answer:

the large fish will move with a velocity of 0.833m/s in direction in which it was moving finally

Explanation:

given mass of large fish m1=5kg ; initial velocity of large fish, u1=1m/s

mass of small fish, m2=1kg ; initial velocity of small fish, u2=0

applying law of conservation of momentum before lunch

or m1 v+m2 v = m1u1 +m2u2

or (m1 + m2) v = m1u1 + m2u2

or (5+1) v = (5)×(+1)+(1)×0

or 6 v = 5, or 5/6m/s or v = 0.833m/s

the large fish will move with a velocity of 0.833 m/s in the direction in which it was moving initially.