Question

There are 20 divisions in 4cm of the main scale. The Vernier scale has 10 divisions. what is the least count of the instrument

Answer 1

Answer:

The least count of the instrument is : 0.02cm

Explanation:

It is given that :

• there are 20 divisions in the main scale
• 4cm of the main scale
• Vernier scale has 10 divisions

Therefore,

one mean scale division = 4cm/20 = 1/5 = 0.2

Least Count(LC) = one mean scale division/no. of division in the vernier scale

LC = 0.2/10 = 0.02 cm

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Answer 2

Answer: The instrument's least count will be 0.02 cm according to the given data.

Explanation:

Steps to find the reading :-

• View the primary scale. Find the final visible whole increment that comes before the 0 (zero) mark.
• Read the Vernier measurement on the secondary scale. The division tick mark that aligns best with a mark on the primary scale is this one.
• The two measures should be added.

It follows that:

The primary scale has 20 divisions.

the primary scale's 4 cm

Vernier scale contains ten divisions.

Therefore,

1 MSD = 4cm/20 = 1/5 = 0.2

So, 0.2 is one main scale division.

The Vernier scale's number of divisions divided by one main scale division is the Least Count (LC).

LC = 0.2/10 = 0.02 cm.

Hence, the correct answer is 0.02 cm.

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