Question

Consider a non-empty array of strings inarr where each element is a novena alphanumeric string. Identify and print outstr based on the logie deon . For each element of inarr, find the first smallest length susting contains all the unique case-sensitive) characters of the ce From the identified subsirs assign the substr with the last If more than one substr has the least length corresponding to the element occuring Outs​

Answer 1

Answer:

Consider a non-empty array of strings inarr where each element is a novena alphanumeric string. Identify and print outstr based on the logie deon . For each element of inarr, find the first smallest length susting contains all the unique case-sensitive) characters of the ce From the identified subsirs assign the substr with the last If more than one substr has the least length corresponding to the element occuring Outs

Answer 2

Answer:

Python code to find find the first smallest length susting contains all the unique case-sensitive.

Explanation:

From the above question,

Given an array of strings called "inarr", the task is to identify and print out the substring of each element in "inarr" that contains all the unique characters of the element in a case-sensitive manner. The substring with the smallest length should be selected, and if multiple substrings have the same smallest length, the one occurring last should be chosen.

Here is an implementation in Python that performs the desired actions:

                                  PYTHON CODE

def find_substring(inarr):

 result = []

 for s in inarr:

   substring = ''

   for i in range(len(s)):

     for j in range(i, len(s)):

       substring = s[i:j + 1]

       if len(substring) == len(set(substring)):

         break

     if len(substring) == len(set(substring)):

       break

   result.append(substring)

 return result

inarr = [..., ..., ...] # replace with the actual input array

print(find_substring(inarr))

For more such related questions : https://brainly.in/question/17348344

#SPJ3