Question

How many moles of propane are required to produce 22gm of co2 after combustion

Answer 1

Explanation:

C2H8 + o2 --> 2CO2 + 4h2o

if 20g (molecular mass) propane required 76g CO2

then 22 g of co2 require (20/76)*22

= 5.79g

mole of propane

mole = given mass/ molecular mass

= 5.79/76

=0.076 Mole