Question

Consider a non-interlaced monitor with resolution Nx M, a refresh rate of R frames per Sec, a Horizontal retrace time of Hr. What is the fraction of total refraction time per frame spent in retrace of electron beam?

Answer 1

Explanation:

Ans. Because eight bits constitute a byte, frame-buffer sizes of the systems are as follows: 640 x 480 x 12 bits / 8 = 450KB; 1280 x 1024 x 12 bits / 8 = 1920KB; 2560 x 2048 x 12 bits / 8 = 7680KB; b) How much storage (in bytes) is required for each system if 24 bits per pixel are to be stored?