Physics, asked by subrat345, 9 months ago

Consider a non-spherical conductor shown in the
figure which is given a certain amount of positive
charge. The charge distributes itself on the
surface such that the charge densities are 01. 02
and og at regions 1, 2 and 3 respectively. Then,​

Answers

Answered by PoojaBurra
3

The correct question is:

Consider a non-spherical conductor shown in the figure which is given a certain amount of positive charge. The charge distributes itself on the surface such that the charge densities are σ₁, σ₂ ,σ₃ at regions 1, 2 and 3 respectively. Then

1) σ₁ > σ₂ > σ₃

2) σ₂ > σ₃ > σ₁

3) σ₃ > σ₁ > σ₂

4)) σ₂ > σ₁ > σ₃

Solution:

The charge densities are in the order σ₂ > σ₁ > σ₃

  • Consider any point in the given surface.The net electric field inside the conductor will be zero
  • Charge density is given by the relation

                      \sigma=\frac{Q}{A}

                      \sigma \propto \frac{1}{A}

  • From the figure we see that the areas of the regions 1,2,3 are in the order    A_3>A_1>A_2
  • As charge density is inversly proportional to area  \sigma_1> \sigma_1> \sigma_3
  • Therefore correct answer is option(D) σ₂ > σ₁ > σ₃
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