Question

Consider a refrigerator. What is the coefficient of performance if the heat released is 6.75 watts and the heat added is 3.75 watts?

Answer 1

Answer:

The COP of the refrigerator and air-conditioner can be less than one or greater than one. The above formula also shows that the COP of the heat pump can never be less than one; it is always more than one.

Answer 2

Answer:

The Answer is 1.25

Explanation:

Coefficient of Performance of a refrigerator = Heat Extracted divided by the work input

6.75=Qhigh

3.75=Qlow

Qhigh-Qlow=Work

6.75 - 3.75 = 3                          

$\frac{Qlow}{Work}$ = COP⇒$\frac{3.75}{3}$ = 1.25