Question

Consider a right triangle with legs of length a and b and hypotenuse of length
tha and b and hypotenuse of length o. If k denotes the area of the
triangle then the value of (a + b) equals
(a) c+√k
(b) √c^2 + 4k
(c) c^2/4√k
(d) 4k/c​

Answer 1

Answer:

Answer is second....

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Answer 2

Answer:

(b)

Step-by-step explanation:

consider the right angled triangle with base ( b ) = 3 height (a ) = 4

hypotenuse ( c )= √(3² + 4²) = √(25) = 5

area of a triangle ( k )= (1/2)bh = 1/2*3*4 = 6

so a + b = 3 + 4 = 7

considering option b : √(c² + 4k)

c² = 5² = 25

4k = 4 * 6 = 24

√(c² + 4k) = √(25 + 24 ) = √(49) = ±7

so finally

a + b = √(c² + 4k)