Question

Consider a series combination of two resistors of resistances 10 Ω and 40 Ω across which a potential difference of 5 V is applied. Find the current in the circuit and the potential difference across each resistor.​

Answer 1

Answer:

Explanation:a) combined resistance in series= R  

1

​

+R  

2

​

=6+2=8Ω

(b)I=  

R

V

​

=  

8

4

​

=0.5A

(C) p.d across 6 ohm= IR=6×0.5=3V