Physics, asked by sarvjeetsingh9939, 5 months ago


Consider a small surface area of 1 mm(2) at the top of a
mercury drop of radius 4.0 mm. Find the force exerted
on this area (a) by the air above it (b) by the mercury
below it and (c) by the mercury surface in contact with
it. Atmospheric pressure = 1.0 x 10 (5)Pa and surface
tension of mercury = 0.465 Nm(-1). Neglect the effect of
gravity. Assume all numbers to be exact.​

Answers

Answered by rishabhrai8700
0

Answer:

344433!23445578999^7433467888

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