Question

Consider a soap film on a rectangular frame of wire of area 4×4 cm2 if the area of the soap film is incresed to 4 × 5cm2 the work done in the process will be

Answer 1

Hello dear,

◆ Answer -
W = 8×10^-4 T J

# Given-
A1 = 4×4 cm^2 = 16 cm^2 = 16×10^-4 m^2
A2 = 4×5 cm^2 = 20 cm^2 = 20×10^-4 m^2

# Solution-
Let's assume T be surface tension of the soap film on rectangular frame.

Work done in increasing area is given by-
W = T × 2∆A
W = T × 2 × (A2 - A1)
W = T × 2 × (20×10^-4 - 16×10^-4)
W = 8×10^-4 T J

Work done in increasing area is 8×10^-4 T J.

Hope this is helpful...