Question

Construct a right triangle whose hypotenuse and one side measures 10 cm and 8 cm respectively then construct another triangle whose sides are 4 by 5 times the corresponding side of the triangle how it can be drawn

Answer 1

1)draw the given Triangle
from a draw an angle theta which is an acute angle of any measure
2)by taking a as center cut an arcbe of 1 cm then by taking B1 as center curt an Arc b2a 1cm similarly to the same up till B5
3)join b4b
4)join b5b'//b4b
5)similarly join b'c'
6)a new triangle is formed ab'c'.

Answer 2

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1. Draw a line segment BC = 8 cm.

2. Construct BM perpendicular BC.

3. Taking C as centre and radius as 10 cm, draw an arc that cuts the ray BM at A

4. Join CA to obtain ∆ABC.

5. Below BC, make an acute angle CBX.

6. Along BX mark 5 points B1, B2, B3, B4, B5 such that BB1 = B1B2 = B2 B3 = ......... = B4 B5.

7. Join B5C.

8. From B4, Draw B4C || B5C.

9. From C draw C’A’ CA meeting BA at point A’. Then A’BC’ is the required triangle.

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