Question

Consider a system with main memory of 1024 cost,100 units and secondary memory 4096 costs,10 units what will be the average cost per bit of the same system

Answer 1

Answer:

0.021484375 cost per unit

Step-by-step explanation:

Average Cost Per Bit of System = Total Cost of System(main + secondary) / Total Number of Bits (main + secondary)

Average Cost Per Bit of System = ( 100 + 10 )/ (1024 + 4096)

Average Cost Per Bit of System = 110 / 5120 = 0.021484375 cost per unit

Answer 2

The average cost per bit of the same system is 28  .

Step-by-step explanation:

Given as :

Total cost for 1024 units per bit of Main Memory = 100

Total cost for 4096 units per bit of Secondary Memory = 10

Let The average cost per bit = n

According to question

Average cost per bit = $\dfrac{Total cost of system}{Total number of bits}$

Or,  n = $\dfrac{1024\times 100+4096\times 10}{1024+4096}$

Or,  n = $\dfrac{143360}{1024+4096}$

Or   n = $\dfrac{143360}{5120}$

∴     n = 28 cost per bit

So, The average cost per bit of the same system = n = 28 cost per bit

Hence, The average cost per bit of the same system is 28  . Answer