Math, asked by sdhema223, 2 months ago

Consider a tetrahedral die and roll it twice. What is the probability that the number on the fit
st roll is strictly higher than the number on the second roll? For tetrahedral dice having fourf​

Answers

Answered by Anonymous
2

प्रशिक्षण की जरूरत प्रशिक्षण का उद्देश्य किसी व्यक्ति या समूह के ज्ञान, कौशल व अभिवृत्ति (नॉलेज, स्किल और एटीट्यूड) के ऊपर फोकस किया जाता है। ज्ञान में किसी क्षेत्र विशेष की अवधारणाओं पर व्यापक समझ बनाने के ऊपर फोकस किया जाता है। ... ज्ञान के बारे में एक बात कही जा सकती है कि यह समय के साथ बदलने वाली चीज़ है।

Answered by annasl
0

Answer:

Probability that the number on the first roll is strictly higher than the number on the second roll is 0.375

Step-by-step explanation:

A tetrahedral die has 4 faces.

Given, the die is rolled twice.

the possible outcomes are (1,1) (1,2) (1,3) (1,4) (2,1) (2,2) (2,3) (2,4) (3,1) (3,2) (3,3) (3,4) (4,1) (4,2) (4,3) (4,4)

There are total 16 outcomes

Possible outcomes i,e number on first roll is greater than the number on the second roll are as follows:

(2,1) (3,1) (3,2) (4,1) (4,2) (4,3)

Number of favorable outcomes = 6

Probability that the number on the first roll is strictly higher than the number on the second roll = \frac{6}{16} = 0.375

#SPJ3

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