Question

Consider a tightly wound 100 turn coil of radius 10 cm, carrying a current of 1 A. What is the magnitude of the magnetic field at the centre of the coil ?

Answer 1

Explanation:

Number of turns in the coil N=100

Radius of coil r=0.1 m

Current flowing in the coil I=1 A

Magnetic field at the

center of the coil B= μIN /2r

∴ B= 4π*10-⁷*1*100/ 2*0.1

⟹ B=6.28×10 -⁴ T