Question

Consider a tightly wound 100 turns of a coil of radius 1 cm carrying a current of 1A . What is the magnitude of the magnetic field at the center of the coil ?

Answer 1

You can solve this by using B=[(mue0)×IN]/2a where •mue0 is the permeability of vacuum(4л×10^-7) •I=1A •N=100 •a=10cm and I think the ans: 6.28×10^-6